A Rocket Travelling At 95 M/S Is Accelerated Uniformly To 150m/S In 10 Seconds.What Is The Dispalcement?

a rocket travelling at 95 m/s is accelerated uniformly to 150m/s in 10 seconds.what is the dispalcement?

 

Good Day....

Problem:

a rocket travelling at 95 m/s is accelerated uniformly to 150m/s in 10 seconds.what is the displacement?

Given Data:

d (displacement) = ? unknown

Vi (initial velocity)  =  95 m/s

Vf (final velocity)   =  150 m/s

          t (time)        =   10 seconds

Solution:

First: we need to solve for acceleration to determine the displacement. We can use to formula  a = (Vf-Vi)/t

a = (Vf-Vi)/t

   = (150 m/s - 95 m/s) / 10 s

   =  55 m/s / 10 s

   = 5.5 m/s^2

Second: we will solve for displacement using acceleration 5.5 m/s^2, velocity initial 95 m/s, and time 10 seconds with the formula  d = Vi × t + (a × t^2)/2

d = Vi × t + (a × t^2)/2

  = 95 m/s × 10 s  + (5.5 m/s^2 × (10 s)^2) / 2

  = 950 m  +  (5.5 m/s^2 × 100 s^2) /2  (cancel the unit s^2)

  = 950 m  +  (550 m / 2)

  = 950 m + 275 m

  = 1,225 meters

                 

Answer:

displacement = 1,225 meters

Hope it helps....=)